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12y^2-21y-6=0
a = 12; b = -21; c = -6;
Δ = b2-4ac
Δ = -212-4·12·(-6)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-27}{2*12}=\frac{-6}{24} =-1/4 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+27}{2*12}=\frac{48}{24} =2 $
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